re = /^(\d+(?:\.\d{1,3})?)/m
str = '23.554656561568181681916651651615618
42.8865465465
468
40.541222
0
50'
subst = '$1%'
result = str.gsub(re, subst)
# Print the result of the substitution
puts result
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html