re = /^PT(\d+H)?(\d+M)?(\d+S)?$/m
str = 'PT1H37S
PT1H30M15S
PT0S
PT1H0M0S
PT22H41M59S'
subst = ''
result = str.gsub(re, subst)
# Print the result of the substitution
puts result
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html