re = /\b0+\B/m
str = '092.01.001.220
192.16.092.000
02.1.001.01
010.064.214.210
010.064.000.150
010.000064.017.001
127.00000.0.001
10.0.00.000
010.064.105.201'
subst = ''
result = str.gsub(re, subst)
# Print the result of the substitution
puts result
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html