re = /\s+|^((1[0-9]{1,3})|(20[0-1][0-2])|(200[0-9]))\/((0[0-9])|[0-9]|[1][0-2])\/(([0-2][0-9])|(30)) (([0-1][0-9])|([2][0-4])):([0-6][0-9])/mi
str = '1995/12/01 12:12
1012/12/02 12:34
4012/12/02 12:34
3012/12/02 12:34
2013/12/02 12:34
2007/13/02 12:34
2007/12/02 12:34'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html