re = /^(.+?)$/m
str = 'lt_subcontractor_stat
lt_subcontractor_stat_detail
outbound_inbound_stopfactor_report
comparison_stopratio_parcelratio_report
parcels_paid_twice
pickup_cost_per_parcel
delivery_cost_per_parcel
'
subst = '\'$1\','
result = str.gsub(re, subst)
# Print the result of the substitution
puts result
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html