re = /(\d\d\d\d) (\w\w\w\w\w\w\w\w\w)(\s)(\w\w)/m
str = '1972 31JUL1972 _1
"_" is een word character, "-" is dit niet'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html