re = /(\pL+)(\d+)/m
str = 'Форд23324
Форд23325
Форд23326
Форд23327
Форд23328
Форд23329
Форд23330
Форд23331
Форд23332
Форд23333
Форд23334
Форд23335
Форд23336
'
subst = '$1 $2'
result = str.gsub(re, subst)
# Print the result of the substitution
puts result
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html