# coding=utf8
# the above tag defines encoding for this document and is for Python 2.x compatibility
import re
regex = r"<img.+src=[\'\"](?P<src>.+?)[\'\"].*>"
test_str = ("<table><tr><td><img src='http://newstarget.com/wp-content/uploads/sites/43/2016/10/hillary9-168x95.jpg' width='168' height='95' /></td><td valign='top'>\n"
" Many of us have been wondering exactly how Hillary Clinton has been able to get away with her blatant, obvious corruption for so long now. Even though it’s well known that the federal government protects their own and the Democrats will go above and beyond to avoid condemning a member of their party, Hillary has […] </td></tr></table>\n"
" ")
matches = re.search(regex, test_str, re.IGNORECASE)
if matches:
print ("Match was found at {start}-{end}: {match}".format(start = matches.start(), end = matches.end(), match = matches.group()))
for groupNum in range(0, len(matches.groups())):
groupNum = groupNum + 1
print ("Group {groupNum} found at {start}-{end}: {group}".format(groupNum = groupNum, start = matches.start(groupNum), end = matches.end(groupNum), group = matches.group(groupNum)))
# Note: for Python 2.7 compatibility, use ur"" to prefix the regex and u"" to prefix the test string and substitution.
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Python, please visit: https://docs.python.org/3/library/re.html