import Foundation
let pattern = #"""
(1) (\d{5})([US ]) (\d{2})(\d{3})([A-Z ]{1,3}) (\d{2})(\d.{11}) ([-].\d{8}) ([-+ ]\d{5}[-+ ]\d) ([-+ ]\d{5}[-+]\d) ([0-4]) ([ \d]{4})(\d)
(2) (\d{5}) ([ \d]{3}.[\d ]{4}) ([ \d]{3}.[ \d]{4}) (\d{7}) ([ \d]{3}.[\d ]{4}) ([ \d]{3}.[\d ]{4}) ([ \d]{2}.[\d ]{8})([ \d]{5})(\d)
"""#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"""
1 25544S 98067A 98324.28472222 -.00003657 11563-4 00000+0 0 10
2 25544 51.5908 168.3788 0125362 86.4185 359.7454 16.05064833 05
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
if let firstMatch = regex.firstMatch(in: testString, range: stringRange) {
let result: [String] = (1 ..< firstMatch.numberOfRanges).map { (testString as NSString).substring(with: firstMatch.range(at: $0)) }
print(result)
} else {
print("No matches were found.")
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression