re = /(1) (\d{5})([US ]) (\d{2})(\d{3})([A-Z ]{1,3}) (\d{2})(\d.{11}) ([-].\d{8}) ([-+ ]\d{5}[-+ ]\d) ([-+ ]\d{5}[-+]\d) ([0-4]) ([ \d]{4})(\d)
(2) (\d{5}) ([ \d]{3}.[\d ]{4}) ([ \d]{3}.[ \d]{4}) (\d{7}) ([ \d]{3}.[\d ]{4}) ([ \d]{3}.[\d ]{4}) ([ \d]{2}.[\d ]{8})([ \d]{5})(\d)/
str = '1 25544S 98067A 98324.28472222 -.00003657 11563-4 00000+0 0 10
2 25544 51.5908 168.3788 0125362 86.4185 359.7454 16.05064833 05'
# Print the match result
str.match(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html