# coding=utf8
# the above tag defines encoding for this document and is for Python 2.x compatibility
import re
regex = (r"(1) (\d{5})([US ]) (\d{2})(\d{3})([A-Z ]{1,3}) (\d{2})(\d.{11}) ([-].\d{8}) ([-+ ]\d{5}[-+ ]\d) ([-+ ]\d{5}[-+]\d) ([0-4]) ([ \d]{4})(\d)\n"
r"(2) (\d{5}) ([ \d]{3}.[\d ]{4}) ([ \d]{3}.[ \d]{4}) (\d{7}) ([ \d]{3}.[\d ]{4}) ([ \d]{3}.[\d ]{4}) ([ \d]{2}.[\d ]{8})([ \d]{5})(\d)")
test_str = ("1 25544S 98067A 98324.28472222 -.00003657 11563-4 00000+0 0 10\n"
"2 25544 51.5908 168.3788 0125362 86.4185 359.7454 16.05064833 05")
matches = re.search(regex, test_str)
if matches:
print ("Match was found at {start}-{end}: {match}".format(start = matches.start(), end = matches.end(), match = matches.group()))
for groupNum in range(0, len(matches.groups())):
groupNum = groupNum + 1
print ("Group {groupNum} found at {start}-{end}: {group}".format(groupNum = groupNum, start = matches.start(groupNum), end = matches.end(groupNum), group = matches.group(groupNum)))
# Note: for Python 2.7 compatibility, use ur"" to prefix the regex and u"" to prefix the test string and substitution.
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Python, please visit: https://docs.python.org/3/library/re.html