using System;
using System.Text.RegularExpressions;
public class Example
{
public static void Main()
{
string pattern = @"(\b10\.5\.(29|31|32)\.15\b|\b10\.0\.100\.75\b)";
string input = @"10.5.31.15
45.36.87.12
10.0.100.75
192.168.1.168
10.5.4.15
10.5.32.15
10.10.25.36
10.0.100.56
10.5.29.15";
foreach (Match m in Regex.Matches(input, pattern))
{
Console.WriteLine("'{0}' found at index {1}.", m.Value, m.Index);
}
}
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for C#, please visit: https://msdn.microsoft.com/en-us/library/system.text.regularexpressions.regex(v=vs.110).aspx