re = /^((?:\d){1,3}(?:\.\d{1,3}){0,8})/m
str = '1 text
1.1 text 2
1.2 text 3
2 text 2
3 text 3
3.1 text 3.1
second string of 3.1
third string of 3.1
4.1.2.3.4.5
4.1.2.3.4.5.6.7.8
//I used .split() method to get multiline text from numbered list'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html