re = /^((0[1-9]|[12]\d|3[01])\/(0[3578]|1[02])\/((202[1-9])))$|^((0[1-9]|[12]\d|30)\/(0[469]|11)\/((202[1-9])))$|^((0[1-9]|[1]\d|(2[0-8]))\/(02)\/(202[2-9]))$|^((0[1-9]|[12]\d|3[01])\/(01)\/((202[2-9])))$|^((2[0-8])\/(02)\/(2021))$/m
str = '11/02/2022
'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html