const regex = new RegExp('(?i)([<[]Assembly: Assembly(File|Informational)?Version)\\(\\"[^\\"]*\\"\\)', 'gm')
const str = `# C#
[assembly: AssemblyCopyright("")]
[assembly: AssemblyTrademark("")]
[assembly: AssemblyCulture("")]
[assembly: AssemblyVersion("1.1.0.0")]
[assembly: AssemblyDelaySign(false)]
[assembly: AssemblyKeyFile("")]
[assembly: AssemblyKeyName("")]
[assembly: AssemblyInformationalVersion("1.0.0 JRC")]
# VBasic
<Assembly: AssemblyCulture("")>
<Assembly: AssemblyVersion("1.1.0.0")]
<Assembly: AssemblyDelaySign(false)]
<Assembly: AssemblyKeyFile("")>
<Assembly: AssemblyKeyName("")>
<Assembly: AssemblyInformationalVersion("1.0.0 JRC")>
`;
const subst = `\1("0.1.2.3")`;
// The substituted value will be contained in the result variable
const result = str.replace(regex, subst);
console.log('Substitution result: ', result);
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for JavaScript, please visit: https://developer.mozilla.org/en/docs/Web/JavaScript/Guide/Regular_Expressions