import Foundation
let pattern = #"^(?<year>\d{4})(?:(?<month>\d{2})(?:(?<day>\d{2})(?:(?<hour>\d{2})(?:(?<minute>\d{2})(?:(?<second>\d{2})(?:.(?<millis>\d{3})(?:\[(?:(?<offsetSign>[+-]?)(?<offsetHour>\d{1,2}))(?:.(?<offsetMin>\d{2}))?(?::(?<tz>.*)?)?\])?)?)?)?)?)?)?$"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
1996
199610
19961005
1996100513
199610051322
19961005132200
19961005132200.124
19961005132200.124[-5]
19961005132200.124[-5:EST]
19961005132200.124[-5.30:EST]
19961005132200.124[-5.30:]
19961005132200.124[-5.30]
19961005132200.124[+5]
19961005132200.124[+5.30]
19961005132200.124[+5:EST]
19961005132200.124[+5.30:EST]
19961005132200.124[+5.30:]
19961005132200.124[5]
19961005132200.124[5.30]
19961005132200.124[5:EST]
19961005132200.124[5.30:EST]
19961005132200.124[5.30:]
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression