re = /^(?<year>\d{4})(?:(?<month>\d{2})(?:(?<day>\d{2})(?:(?<hour>\d{2})(?:(?<minute>\d{2})(?:(?<second>\d{2})(?:.(?<millis>\d{3})(?:\[(?:(?<offsetSign>[+-]?)(?<offsetHour>\d{1,2}))(?:.(?<offsetMin>\d{2}))?(?::(?<tz>.*)?)?\])?)?)?)?)?)?)?$/m
str = '1996
199610
19961005
1996100513
199610051322
19961005132200
19961005132200.124
19961005132200.124[-5]
19961005132200.124[-5:EST]
19961005132200.124[-5.30:EST]
19961005132200.124[-5.30:]
19961005132200.124[-5.30]
19961005132200.124[+5]
19961005132200.124[+5.30]
19961005132200.124[+5:EST]
19961005132200.124[+5.30:EST]
19961005132200.124[+5.30:]
19961005132200.124[5]
19961005132200.124[5.30]
19961005132200.124[5:EST]
19961005132200.124[5.30:EST]
19961005132200.124[5.30:]
'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html