# coding=utf8
# the above tag defines encoding for this document and is for Python 2.x compatibility
import re
regex = r"(http|https)?:\/\/(www\.)?vimeo.com\/(?:channels\/(?:\w+\/)?|groups\/([^\/]*)\/videos\/|)(\d+)(?:|\/\?)"
test_str = ("Vimeo Regex\n\n"
"# plain ok\n"
"https://vimeo.com/62092214\n"
"http://vimeo.com/62092214\n"
"https://www.vimeo.com/62092214\n\n"
"# plain not ok\n"
"http://vimeo/62092214\n"
"http://vimeo.com/foo\n\n"
"# channels ok:\n"
"https://vimeo.com/channels/documentaryfilm/128373915\n\n"
"# channels not ok:\n"
"https://vimeo.com/channels/foo-barr/documentaryfilm/128373915\n\n"
"# groups ok:\n"
"https://vimeo.com/groups/musicvideo/videos/126199390\n\n"
"# groups not ok:\n"
"http://vimeo.com/groups/musicvideo/vid/126199390\n\n"
"# attributes ok:\n"
"https://vimeo.com/62092214?query=foo\n\n"
"# attributes not ok:\n"
"https://vimeo.com.omomom/62092214?query=foo")
matches = re.finditer(regex, test_str)
for matchNum, match in enumerate(matches, start=1):
print ("Match {matchNum} was found at {start}-{end}: {match}".format(matchNum = matchNum, start = match.start(), end = match.end(), match = match.group()))
for groupNum in range(0, len(match.groups())):
groupNum = groupNum + 1
print ("Group {groupNum} found at {start}-{end}: {group}".format(groupNum = groupNum, start = match.start(groupNum), end = match.end(groupNum), group = match.group(groupNum)))
# Note: for Python 2.7 compatibility, use ur"" to prefix the regex and u"" to prefix the test string and substitution.
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Python, please visit: https://docs.python.org/3/library/re.html