re = /\(?\b([0-9]{3})\)?([0-9]{3})?([0-9]{4})\b/m
str = '1234567890
99999999999999
hello world1234567890
123-456-7890
0123456789
123.456.7890
123 456 7890
8054448445
3104448445
8187558094
310
'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html