import Foundation
let pattern = #"([(\s0-9]+)([lL]\.?)([)\s]+)"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"""
2 l.
2l.
2l
cuatro l
lateral
1l.
l.
L.
ls.
Ls.
L
l
(l)
(L)
(ls.)
(Ls.)
(ls)
(Ls)
l.
l.
L
l
3l.
2l.
2l.
4 l.
4l
5L.
lateral
literal
1 litro
1l.
1 l. de agua
1/2 L. de zumo
(l)
1l
l.
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression