re = /^(0[1-9]|[1-9][ABab\d])\d{3}$/m
str = '00000
00123
01200
20456
99123
78646
2A000
'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html