re = /\s*(?P<IP>(\d{1,3}\.?){4})\s+(?P<MAC>\S+)\s+(?P<TYPE>\w+)/m
str = 'Интерфейс: 192.168.0.4 --- 0x8
адрес в Интернете Физический адрес Тип
192.168.0.1 34-e0-cf-64-9e-68 динамический
192.168.0.7 38-d5-47-17-5f-23 динамический
192.168.0.255 ff-ff-ff-ff-ff-ff статический
224.0.0.22 01-00-5e-00-00-16 статический
224.0.0.251 01-00-5e-00-00-fb статический
224.0.0.252 01-00-5e-00-00-fc статический
239.255.255.250 01-00-5e-7f-ff-fa статический
255.255.255.255 ff-ff-ff-ff-ff-ff статический'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html