import Foundation
let pattern = #"^([a-zA-Z]{0,3}\$\s*)?(([1-9]\d{0,2})(,\d{3}){0,3}(,\d{3})|(\d{1,14}))(\.\d{2})?$"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
/* Valid */
$9
R$9.99
R$ 9.99
BRL$9.99
9
99999999999999
99999999999999.99
9,000.99
99,000.99
999,000.99
9,000,000.99
99,000,000.99
999,000,000.99
999,000,000.99
9,000,000,000.99
99,000,000,000.99
999,000,000,000.99
9,000
99,000
999,000
9,000,000
99,000,000
999,000,000
999,000,000
9,000,000,000
99,000,000,000
999,000,000,000
/* Invalid */
R9
R$9,99
999999999999999
999999999999999.99
0,000.99
09,000.99
099,000.99
0,000,000.99
09,000,000.99
099,000,000.99
099,000,000.99
0,000,000,000.99
09,000,000,000.99
099,000,000,000.99
0,999
,99,000
99,9,000
99,99,000
9,9999,000
9,99,000,000
,999999,000
99,99,000,000
999,999999,000
999999,000,000
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression