import Foundation
// WARNING: You included a flag that Swift doesn't support: u
// When this flag is set, it makes the pattern and subject strings to be treated as unicode.
// Swift already treats the pattern and subject strings as unicode by default, so including this flag is redundant.
let pattern = ##"(^(?<date>\d{1,2}\/\d{1,2}\/\d{1,2}),\s(?<time>\d{1,2}:\d{1,2})\s-\s(?<user>.*?):\s)|(?<word>\w+(?:\'\w+)?|[\x{1F600}-\x{1F64F}]|[\x{1F300}-\x{1F5FF}]|[\x{1F680}-\x{1F6FF}]|[\x{2600}-\x{26FF}]|[\x{2700}-\x{27BF}]|[^\w\s~"!@#$%*()_+-=¹²³§ªº`^{}[\]<>,.;:?\/\\\|\n\r\t])"##
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
3/30/20, 17:06 - Me: Hi brow! I need to test some regex.
3/30/20, 17:06 - John Doe: 👍👍👍 Let's do it!
3/30/20, 17:08 - Me: ⚡️🦄🧀🏀🤪🎺🎪💾🚽📎💕💯✅ 🇯🇵 🕔➡️👶🚴👌👽
3/30/20, 17:10 - Someone: 🐵🙈🙉🙊🐒 We're talking emoji language?
https://regex101.com/library
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression