re = /(?<=\/)[\w\-.]+(?=(\?|(\s*)$|(\/)$))/
str = 'https://www.tokopedia.com/laris88/tempat-bumbu-dapur-4-sekat-joyfeel-1047-seasoning-storage-merah-muda
https://www.tokopedia.com/tenonenonet/gift-box-kotak-kado-souvenir-hadiah-ukuran-14-x-14-x-5cm-plus-tali?whid=0
https://www.tokopedia.com/tenonenonet/gift-box-kotak-kado-souvenir-hadiah-ukuran-14-x-14-x-5cm-plus-tali
https://gql.tokopedia.com/tokopedia.com/
https://gql.tokopedia.com/ceriasmart/
https://gql.tokopedia.com/22ceria.-smart/
tokopedia\\.com/([^/]+[\\w])
todo
i want grab only "gift-box-kotak-kado-souvenir-hadiah-ukuran-14-x-14-x-5cm-plus-tali" without end character \'?\'
tokopedia\\.com/[^/]*[\\w\\/](.*)|[?!\\?]'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html