import Foundation
let pattern = #"((([a-z]\[[^\]]+\])(.{1}))?(\s*\=\>\s*)((([a-z]\[[^\]]+\])|([a-z].))(.{1})([A-Z]?)))?(\s*\/\/.*)?"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = ##"""
// Алгоритм умножения. Формат ленты: [*]1111#111=*
// Множество: Q; Начальное значение: q[0]; Конечное значение: q*;
// Символ пустой ячейки: _; Символ перехода влево: L; Символ перехода вправо: R
q[0]1 => q[0]1R //2312312323
q[0]# => q[1]#R
q[0]* => q[0]*R
q[1]1 => q[2]aR
q[2]1 => q[2]1L
q[2]# => q[3]#L
q[2]= => q[2]=L
q[2]a => q[2]aL
q[3]1 => q[4]aR
q[3]a => q[3]aL
q[3]* => q[6]*R
q[4]1 => q[4]1R
q[4]# => q[4]#R
q[4]= => q[4]=R
q[4]a => q[4]aR
q[4]* => q[5]1R
q[5]_ => q[2]*L
q[6]# => q[7]#R
q[6]a => q[6]1R
q[7]1 => q[2]aR
q[7]= => q[8]=L
q[7]a => q[7]aR
q[8]# => q*#
q[8]a => q[8]1L
"""##
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression