import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Example {
public static void main(String[] args) {
final String regex = "((([a-z]\\[[^\\]]+\\])(.{1}))?(\\s*\\=\\>\\s*)((([a-z]\\[[^\\]]+\\])|([a-z].))(.{1})([A-Z]?)))?(\\s*\\/\\/.*)?";
final String string = "// Алгоритм умножения. Формат ленты: [*]1111#111=*\n"
+ "// Множество: Q; Начальное значение: q[0]; Конечное значение: q*;\n"
+ "// Символ пустой ячейки: _; Символ перехода влево: L; Символ перехода вправо: R\n"
+ "q[0]1 => q[0]1R //2312312323\n"
+ "q[0]# => q[1]#R\n"
+ "q[0]* => q[0]*R\n"
+ "q[1]1 => q[2]aR\n"
+ "q[2]1 => q[2]1L\n"
+ "q[2]# => q[3]#L\n"
+ "q[2]= => q[2]=L\n"
+ "q[2]a => q[2]aL\n"
+ "q[3]1 => q[4]aR\n"
+ "q[3]a => q[3]aL\n"
+ "q[3]* => q[6]*R\n"
+ "q[4]1 => q[4]1R\n"
+ "q[4]# => q[4]#R\n"
+ "q[4]= => q[4]=R\n"
+ "q[4]a => q[4]aR\n"
+ "q[4]* => q[5]1R\n"
+ "q[5]_ => q[2]*L\n"
+ "q[6]# => q[7]#R\n"
+ "q[6]a => q[6]1R\n"
+ "q[7]1 => q[2]aR\n"
+ "q[7]= => q[8]=L\n"
+ "q[7]a => q[7]aR\n"
+ "q[8]# => q*#\n"
+ "q[8]a => q[8]1L";
final Pattern pattern = Pattern.compile(regex);
final Matcher matcher = pattern.matcher(string);
while (matcher.find()) {
System.out.println("Full match: " + matcher.group(0));
for (int i = 1; i <= matcher.groupCount(); i++) {
System.out.println("Group " + i + ": " + matcher.group(i));
}
}
}
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Java, please visit: https://docs.oracle.com/javase/7/docs/api/java/util/regex/Pattern.html