import Foundation
let pattern = #"(?xm) (?(DEFINE) (?<byte> 2[0-4]\d | 25[0-5] | 1\d\d | [1-9]?\d) ) ^ (10 (?:\.(?&byte)){3} | 172 \. (?: 1 [6-9] | 2\d | 3[01] ) (?:\.(?&byte)){2} | 192 \. 168 (?:\.(?&byte)){2} | ) $"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"""
10.0.0.0
10.1.2.3
10.255.255.255
172.16.0.0
172.25.1.2.3
172.31.255.255
12.34.56.78
123.456.789.0
192.168.0.555
192.168.0.0
192.168.1.2
192.168.255.255
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression