re = /([A-Z]{3})-([A-Z]{3})-([A-Z]{3})/m
str = 'Welcome to RegExr v2.0 by gskinner.com!
Edit the Expression & Text to see matches. Roll over matches or the expression for details. Undo mistakes with ctrl-z. Save & Share expressions with friends or the Community. A full Reference & Help is available in the Library, or watch the video Tutorial.
pippo
Sample text for testing:
abcdefghijklmnopqrstuvwxyz ABCDEFGHIJKLMNOPQRSTUVWXYZ
abcdefghijk.lmn.opqrstuvwxyz ABCD.EFG.HIJKLMN-OPQ-RSTUVWXYZ
0123456789 +-.,!@#$%^&*();\\/|<>"\'
12345 -98.7 3.141 .6180 9,000 +42
555.123.4567 +1-(800)-555-2468
foo@demo.net bar.ba@test.co.uk
www.demo.com http://foo.co.uk/
http://regexr.com/foo.html?q=bar'
subst = '==> sostituto: $3:$1:$2 ==> originale: **$&**'
result = str.gsub(re, subst)
# Print the result of the substitution
puts result
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html