re = /\b(0*(25[0-5]|2[0-4]\d|[01]?\d\d?)\.){3}(0*(25[0-5]|2[0-4]\d|[01]?\d\d?))\b/m
str = '1.1.1.1
2.2.2.2
10.10.10.10
100.100.100.100
125.125.125.125
250.250.250.250
255.255.255.255
0101.0101.0101.0101
00000102.00000102.00000102.00000102
0.0.0.0
256.256.256.256
1234.1234.1234.1234
'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html