re = /^(\+?\d{0,2})?\s?[\D]?\(?(\d{3})\)?[\D]?(\d{3})[\D]?(\d{4})$/m
str = '1
12
123
1234
12345
123456
1234567
12345678
123456789
1234567890
+1234567890
+123-456-7890
+123 456 7890
123 456 7890
123-456-7890
123 456-7890
123-456 7890
123-4567890
123456-7890
(234) 567 8940
(234)-567-8490
(425)512-7497
+919560862817
9560862817
956 086 2817
sgsdfgsd sdgsd sdg
asdf
+448897687877
'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html