use strict;
my $str = '2015 64 Fiat 500 S Hatchback 1.2 Manual Petrol Silver White 13000 £7,495
2012 12 Fiat 500 Lounge Hatchback 1.2 Manual Petrol White 9000 £5,495
2014 14 Fiat Panda Pop Hatchback 1.2 Manual Petrol White 30000 £4,695
2009 09 Fiat 500 Pop Hatchback 1.2 Manual Petrol Yellow 31000 £4,295';
my $regex = qr/\d+\K\d{3}(?=\h£)/p;
my $subst = ',$0';
my $result = $str =~ s/$regex/$subst/rg;
print "The result of the substitution is' $result\n";
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Perl, please visit: http://perldoc.perl.org/perlre.html