import Foundation
let pattern = #"""
(((([0][1-9]|1\d)|2[0-9])|(([12]\d|0[1-9])|(3[01]))(?!\.02))\.(0[1-9]|1[0-2])\.(\d{4}|\d{2}))
|
((0(1|[3-9])|1[0-2])\.(0[1-9]|[12]\d|3[01])|02\.([1-9]|[12]\d))\.(\d{4}|\d{2})
"""#
let regex = try! NSRegularExpression(pattern: pattern, options: [.anchorsMatchLines, .allowCommentsAndWhitespace])
let testString = #"""
Ftet30.02.1999
29.02.1999
28.03.1999
01.02.1999
29.00.1123
00.00.1999
01.01.11_+L12.22.2121
02.28.1111
01.12
09.18.1r11.30.67
Ftet30.02.1999
01.01.11_+L12.22.2121
02.30.11
03.30.11
02.29.11
02.30.12
02.10.12
09.18.1r11.30.67
Ftet30.02.1999
01.01.11_+L12.22.2121
09.18.1r11.30.67
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression