re = /(((([0][1-9]|1\d)|2[0-9])|(([12]\d|0[1-9])|(3[01]))(?!\.02))\.(0[1-9]|1[0-2])\.(\d{4}|\d{2}))
|
((0(1|[3-9])|1[0-2])\.(0[1-9]|[12]\d|3[01])|02\.([1-9]|[12]\d))\.(\d{4}|\d{2})/mx
str = 'Ftet30.02.1999
29.02.1999
28.03.1999
01.02.1999
29.00.1123
00.00.1999
01.01.11_+L12.22.2121
02.28.1111
01.12
09.18.1r11.30.67
Ftet30.02.1999
01.01.11_+L12.22.2121
02.30.11
03.30.11
02.29.11
02.30.12
02.10.12
09.18.1r11.30.67
Ftet30.02.1999
01.01.11_+L12.22.2121
09.18.1r11.30.67'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html