const regex = /(((([0][1-9]|1\d)|2[0-9])|(([12]\d|0[1-9])|(3[01]))(?!\.02))\.(0[1-9]|1[0-2])\.(\d{4}|\d{2}))
|
((0(1|[3-9])|1[0-2])\.(0[1-9]|[12]\d|3[01])|02\.([1-9]|[12]\d))\.(\d{4}|\d{2})/gm;
// Alternative syntax using RegExp constructor
// const regex = new RegExp('(((([0][1-9]|1\\d)|2[0-9])|(([12]\\d|0[1-9])|(3[01]))(?!\\.02))\\.(0[1-9]|1[0-2])\\.(\\d{4}|\\d{2}))
|
((0(1|[3-9])|1[0-2])\\.(0[1-9]|[12]\\d|3[01])|02\\.([1-9]|[12]\\d))\\.(\\d{4}|\\d{2})', 'gm')
const str = `Ftet30.02.1999
29.02.1999
28.03.1999
01.02.1999
29.00.1123
00.00.1999
01.01.11_+L12.22.2121
02.28.1111
01.12
09.18.1r11.30.67
Ftet30.02.1999
01.01.11_+L12.22.2121
02.30.11
03.30.11
02.29.11
02.30.12
02.10.12
09.18.1r11.30.67
Ftet30.02.1999
01.01.11_+L12.22.2121
09.18.1r11.30.67`;
// Reset `lastIndex` if this regex is defined globally
// regex.lastIndex = 0;
let m;
while ((m = regex.exec(str)) !== null) {
// This is necessary to avoid infinite loops with zero-width matches
if (m.index === regex.lastIndex) {
regex.lastIndex++;
}
// The result can be accessed through the `m`-variable.
m.forEach((match, groupIndex) => {
console.log(`Found match, group ${groupIndex}: ${match}`);
});
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for JavaScript, please visit: https://developer.mozilla.org/en/docs/Web/JavaScript/Guide/Regular_Expressions