const regex = new RegExp('step.+\\s+script: \\".*blr/(.*).py\\"\\s+.*\\s+args: \\[([\\"\\w\\W\\s]+?)\\]\\n', 'gm')
const str = `step1:
script: "/workspace/feature-test-lib/tests/upgrade_blr/BQT.py"
skip: 0
args: ["testbed"]
step2:
script: "/workspace/feature-test-lib/tests/upgrade_blr/DC_init.py"
skip: 0
args: ["testbed", "dcinit"]
step3:
script: "/workspace/feature-test-lib/tests/upgrade_blr/sensor_upgrade.py"
skip: 0
args: ["testbed", "upgrade"]
step4:
script: "/workspace/feature-test-lib/tests/upgrade_blr/Apply_Policy.py"
skip: 0
args: ["testbed"]
step5:
script: "/workspace/feature-test-lib/tests/upgrade_blr/sensor_checks.py"
skip: 0
args: ["testbed"]
step6:
script: "/workspace/feature-test-lib/tests/upgrade_blr/delete_device.py"
skip: 0
args: ["testbed", "dcinit"]
step7:
script: "/workspace/feature-test-lib/tests/upgrade_blr/DC_init.py"
skip: 0
args: ["testbed", "dcinit"]
`;
const subst = `\1, \2`;
// The substituted value will be contained in the result variable
const result = str.replace(regex, subst);
console.log('Substitution result: ', result);
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for JavaScript, please visit: https://developer.mozilla.org/en/docs/Web/JavaScript/Guide/Regular_Expressions