re = /(.*)p\.PERSONAL=[^&]*(.*)/
str = 'zeit.BUCHUNGSTAG=[2017-11-01T00%3A00%3A00;2018-02-01T23%3A59%3A59]&_viewjoins=zeit|ba|ma|p&p.PERSONAL=in[deil_felix;lechner_carina]&fdf=dfuebfek
p.PERSONAL=in[deil_felix;lechner_carina]&zeit.BUCHUNGSTAG=[2017-11-01T00%3A00%3A00;2018-02-01T23%3A59%3A59]&_viewjoins=zeit|ba|ma|p'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html