import Foundation
let pattern = #"((?:\+|00)[17](?: |\-|\.)?|(?:\+|00)[1-9]\d{0,2}(?: |\-|\.)?|(?:\+|00)1\-\d{3}(?: |\-|\.)?)?(0\d|\([0-9]{3}\)|[1-9]{0,3})(?:((?: |\-|\.)[0-9]{2}){4}|((?:[0-9]{2}){4})|((?: |\-|\.)[0-9]{3}(?: |\-|\.)[0-9]{4})|([0-9]{7}))"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"""
12345678901
12345678901x1234
345678901x1234
12344678901
12345678901
12345678901
12345678901
+4112345678
+441234567890
1 (234) 567-8901
1 (234) 567-8901 x1234
01 23 45 56 78
335.23.23.23.23
0689912549
+33698912549
+33 6 79 91 25 49
+33-6-79-91-25-49
(555)-555-5555
555-555-5555
+1-238 6 79 91 25 49
+1-555-532-3455
+15555323455
55555555555555555555555555
+7 06 79 91 25 49
935 263223 64 949
067 9 91 254 9
331 23 45 56 78
331.23.45.56.78
331 23 45 56.78
33123455678
2312523125
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression