import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Example {
public static void main(String[] args) {
final String regex = "^(.*?) = \\{ Hash=(?P<hash>\\d*), X=(?P<x>\\d*), Y=(?P<y>\\d*), Rot=(?P<rot>\\d*), Flip=(?P<flip>\\d*), Var=(?P<var>\\d*) \\}";
final String string = "Language = \"Traditional Chinese\"\n"
+ "Hideout Name = \"藏身處 - 羅雀後街\"\n"
+ "Hideout Hash = 62635\n\n"
+ "倉庫 = { Hash=3230065491, X=265, Y=227, Rot=0, Flip=0, Var=0 }\n"
+ "公會倉庫 = { Hash=139228481, X=340, Y=231, Rot=15326, Flip=0, Var=0 }\n"
+ "傳送點 = { Hash=1224707366, X=298, Y=385, Rot=22179, Flip=0, Var=1 }\n"
+ "工藝台 = { Hash=2059629901, X=308, Y=288, Rot=32768, Flip=0, Var=4 }\n"
+ "黃金地球儀 = { Hash=2306038834, X=298, Y=227, Rot=0, Flip=0, Var=0 }\n"
+ "娜瓦莉 = { Hash=693228958, X=322, Y=260, Rot=32768, Flip=0, Var=0 }\n"
+ "埃哈 = { Hash=2684274993, X=325, Y=191, Rot=34826, Flip=0, Var=0 }\n"
+ "艾瓦 = { Hash=2115859440, X=265, Y=207, Rot=16384, Flip=0, Var=0 }\n"
+ "赫蓮娜 = { Hash=845403974, X=314, Y=238, Rot=47093, Flip=0, Var=0 }";
final Pattern pattern = Pattern.compile(regex, Pattern.MULTILINE);
final Matcher matcher = pattern.matcher(string);
while (matcher.find()) {
System.out.println("Full match: " + matcher.group(0));
for (int i = 1; i <= matcher.groupCount(); i++) {
System.out.println("Group " + i + ": " + matcher.group(i));
}
}
}
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Java, please visit: https://docs.oracle.com/javase/7/docs/api/java/util/regex/Pattern.html