import Foundation
let pattern = #"(\d+)(?<!10)(?<!127)\.(\d+)(?<!192\.168)(?<!172\.(1[6-9]|2[0-9]|3[0-1]))\.(\d+)\.(\d+)"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"""
No match
172.16.1.1
172.16.0.0
172.16.0.0
172.31.0.1
172.20.22.22
10.255.255.255
192.168.1.1
192.168.12.34
192.168.111.222
127.255.255.255
127.0.4.4
127.0.0.1
127.255.255.255
127.123.123.123
127.1.1.1
127.12.23.56
Match
172.15.2.2
172.33.33.33
192.167.1.1
192.169.1.1
207.168.207.11
207.168.207.22
192.2.199.199
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression