import Foundation
let pattern = #"^(((0)|([1-9]\d?)|(1\d\d)|(2[0-5]{2}))\.?){0,3}((0)|([1-9]\d?)|(1\d\d)|(2[0-5]{2}))?$"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
255.255.255.255
192.168.0.1
0.0.0.0
192.168.0.
192.168.0
192.1
0
33.33.33.33
2.2.99
255.255.255.255.
192.168.0.270
0.0.0.a
255.255.255. 255
192.168.0..
0.0.00.0
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression