import Foundation
let pattern = #"(?=<[^<]*\s+title="([^"]*)")|<\s*a[^>]*>([^<]*)(?:[^\/]*[^a]*[^>]*)(?<=[>])([^<]*)"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = ##"""
<p title="caca"></p>
<p> </p>
<b>
</b>
<B>title=" gdd "</B>
<i title="caca">dsfgjdgfs</i>
<i title=" boudin ">dsfgjdgfs</i>
<i> </i>
<i> </i>
<strong></strong>
<a>hello</a>
<i style="color: orange"></i>
<a href="#"> bizurot </a> !probleme
<o: class="ms-crap"></o>
<a href="#" title=" kameleo " > test </a> !probleme <a href="#"> cramoute </a> !probleme
<a href="#" title=" banane " > test <strong>hello</strong> asaidali </a><a href="#"> hdsfahsdgf </a> !probleme </br>
<p>Not empty</p>
<p>Not
empty</p>
<i>
</i>
"""##
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression