import Foundation
let pattern = ##"(((((#)|())(([ \t\n]+|()))([a-zA-Z0-9]+)([ \t\n]+))|())((([ \t\n]+|()))((move|mult)|([a-z]+)))((([ \t\n]+|()))(:))((([ \t\n]+|()))([a-zA-Z0-9,&\* \t\"\n\[\]]+))(;))|((([ \t\n]+|()))((save|end)|([a-z]+))(([ \t\n]+|()))(;))"##
let regex = try! NSRegularExpression(pattern: pattern)
let testString = ##"""
{
stream: gogo;
move: some, reg1;
#jix mult: &num, reg2;
push: reg2;
sus : 0x20;
add : him, her;
#goto
jump: loop;
dec : him, *reg2;
#get
add : onu, buna;
jump: goto;
#mydear move: "moses", rgb[8];
save ;
end ;
}
{
move: mos, reg1;
mult: &num, reg2;
push: reg2;
int : 0x20;
#lab
add : him, her;
jump: loop;
#mos
dec: him, *reg2;
#inst
add: onu, buna;
jump: lab;
save;
end;
}
{
inc: moses, to;
#io
push: him;
#kim
jump: frame;
}
okbro () {
dec: him, beat;
#his
push: him;
jump: main;
ret; }
"""##
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression