re = /^((1\d{2}|2[0-4]\d|25[0-5]|[1-9]?\d)(\.(?=\d)|(?!\d))){4}(\/([12]?\d|3[0-2]))?$/m
str = '10.238.51.19
12.89.119.255/30
12.89.119.25
1.2.3.4/24
0.0.0.0/0
00.00.00.00
0.0.0.0.0
1.1..123
1.1.1234.123
1.1.1.123/
1.1.456.78
'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html