import Foundation
let pattern = #"(\+?(\b1)?[\ .\/-]?((?(2)|(\b))|(\())\d{3}(?(?<=\(\d{3})\)|)[\ .\/-]?)?(?(1)|\b)\d{3}[\ .\/-]?\d{4}[\ ]?([xX][\ ]?\d{1,5})?\b"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
+ (513)899-1888
5138991888
8991888
1 5138991888
+5138991888
(513)8991888
1(513)8991888
(5138991888
+1 513-899-1888
1/513-899-1888
1(513)899-1888 X 8888
+1 513 899-1888 x 11111
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression