re = /^(([1-9]\d{0,2}((,\d{3})*|(\d{3})*))|0?)(\.\d+)?$/m
str = 'Capture the following numbers
1
0
1223
332243243423243243243423423243
12
1000000000
111,000,000
1000.000398
1,123,333.2222222
1.22222222
1,234,345,673,345,345,345.123455
1222222222
0.123345
.1234
012,312
.12332
1000.122.122
1,231,423,434.3746472773640000000000
Don\'t Capture:
2000..0000
,111.45
start of line
#first is 1 - 3 digits
# can\'t start with zero
# unless the zero is followed by a period
#then optional (optional comma then 3 digits)
#then optional (period then unlimited digits)
end of line
'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html