re = /^((([1-9][0-9]{0,2})(,\d{3})*(\.\d+)?)|(([1-9][0-9]*)(\.\d+)?))$/m
str = '0,999,999,999,999,999.0
10,999,999,999,999,9899.9
99,999
9.99
09,999
0999998
09999
9.9
999,99
9,999
999.0
abc123
66666666666666666666.098
888888888
0.999'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html