import Foundation
let pattern = #"^(["']?)(\$?([0-9]{1,3},([0-9]{3},?)*[0-9]{3}|[0-9]{1,3})((.[0-9]{0,3})[0-9]{0,10})?)\1$"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
123456
123.
.
.123
123.154574
.545.4584
+1454
+487.54587
-54587.7487
.1225-
.456+
454.4+
454.455874
45.45745687687.5678
45,547
45,5
,154567891021
0,154567891021
123,1023458748
4546587,54587867
578,4
0
.123
0.00145
0.0
012345678910
1,345.154
4,330,234.34
5.545445454
3,023,123.34
12.1
5,356.12345678910
1.20
1.01
0.52
125.30
158,265.36
100,100,100,123,125,568,000.00
""
''
"1"
'1'
"123"
'123'
"123.1"
'0'
"123.12345647891"
"19,741.24"
1234567891023154546574568768767866876767676876584764646546546465465464564564.240
"191741.240"
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression