import Foundation
let pattern = #"^(\d{4})(-(0[1-9]|1[0-2])(-([12]\d|0[1-9]|3[01]))([T\s]((([01]\d|2[0-3])((:)[0-5]\d))([\:]\d+)?)?(:[0-5]\d([\.]\d+)?)?([zZ]|([\+-])([01]\d|2[0-3]):?([0-5]\d)?)?)?)$"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
2009-12T12:34
2009
2009-05-19T08:39:22.000Z
2009-05-19
2009-05-19
20090519
2009123
2009-05
2009-123
2009-222
2009-001
2009-W01-1
2009-W51-1
2009-W511
2009-W33
2009W511
2009-05-19
2009-05-19 00:00
2009-05-19 14
2009-05-19 14:31
2009-05-19 14:39:22
2009-05-19T14:39Z
2009-W21-2
2009-W21-2T01:22
2009-139
2009-05-19 14:39:22-06:00
2009-05-19 14:39:22+0600
2009-05-19 14:39:22-01
20090621T0545Z
2007-04-06T00:00
2007-04-05T24:00
2010-02-18T16:23:48.5
2010-02-18T16:23:48,444
2010-02-18T16:23:48,3-06:00
2010-02-18T16:23.4
2010-02-18T16:23,25
2010-02-18T16:23.33+0600
2010-02-18T16.23334444
2010-02-18T16,2283
2009-05-19 143922.500
2009-05-19 1439,55
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression