const regex = new RegExp('^(\\d{4})(-(0[1-9]|1[0-2])(-([12]\\d|0[1-9]|3[01]))([T\\s]((([01]\\d|2[0-3])((:)[0-5]\\d))([\\:]\\d+)?)?(:[0-5]\\d([\\.]\\d+)?)?([zZ]|([\\+-])([01]\\d|2[0-3]):?([0-5]\\d)?)?)?)$', 'gm')
const str = ` 2009-12T12:34
2009
2009-05-19T08:39:22.000Z
2009-05-19
2009-05-19
20090519
2009123
2009-05
2009-123
2009-222
2009-001
2009-W01-1
2009-W51-1
2009-W511
2009-W33
2009W511
2009-05-19
2009-05-19 00:00
2009-05-19 14
2009-05-19 14:31
2009-05-19 14:39:22
2009-05-19T14:39Z
2009-W21-2
2009-W21-2T01:22
2009-139
2009-05-19 14:39:22-06:00
2009-05-19 14:39:22+0600
2009-05-19 14:39:22-01
20090621T0545Z
2007-04-06T00:00
2007-04-05T24:00
2010-02-18T16:23:48.5
2010-02-18T16:23:48,444
2010-02-18T16:23:48,3-06:00
2010-02-18T16:23.4
2010-02-18T16:23,25
2010-02-18T16:23.33+0600
2010-02-18T16.23334444
2010-02-18T16,2283
2009-05-19 143922.500
2009-05-19 1439,55`;
// Reset `lastIndex` if this regex is defined globally
// regex.lastIndex = 0;
let m;
while ((m = regex.exec(str)) !== null) {
// This is necessary to avoid infinite loops with zero-width matches
if (m.index === regex.lastIndex) {
regex.lastIndex++;
}
// The result can be accessed through the `m`-variable.
m.forEach((match, groupIndex) => {
console.log(`Found match, group ${groupIndex}: ${match}`);
});
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for JavaScript, please visit: https://developer.mozilla.org/en/docs/Web/JavaScript/Guide/Regular_Expressions